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Center of gravity of a portion of cylinder

  1. Apr 24, 2014 #1
    Attachments
    1. Figure # 1
    2. Figure # 2 reproduced from http://www.lmnoeng.com/Volume/InclinedCyl.htmhttp://www.lmnoeng.com/Volume/InclinedCyl.htm

    Description
    The blue is the mass inside a cylinder. In steady condition, I would want to know where its Center of gravity point shall be from either of the ends. Technically its like one mentioned in figure # 2 .It can be regarded as a portion of cylinder

    Trials :
    1) Divided them as a rectangle and a triangle and tried to combine the CG . (answer did not match with 3D models)
    Workout :

    Combined Center of gravity = area of Rectangle*Center of gravity of Rectangle + Area of triangle* Center of gravity of triangle/(Area of Rectangle+ Area of Triangle)
    In this case, (taking all from left end : CG=(500*50+250*33.33)/(500+250)

    No clue why it doesn’t match with the 3D modeling software’s answers. Per software, Center of gravity = 41.89 from left


    Any ideas ?

    figure 1.jpg

    figure 2.jpg
     
  2. jcsd
  3. Apr 24, 2014 #2
    I don't understand how your first picture combines with the second.
     
  4. Apr 24, 2014 #3
    It's just to give an idea. However, if figure 2 is viewed from the side it translates to what I have in figure 1 except for the depth on right hand side of the filled portion
     
  5. Apr 24, 2014 #4

    SteamKing

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    If you look a Fig. 2, you'll see that cross sections cut thru the cylinder perpendicular to the centerline axis form circular segments. You can't simply use the dimensions from the side projection in Fig. 1 and calculate a meaningful result for a circular cylinder. If you had a rectangular tank, you could get away with it.

    You can calculate an approximate value of the longitudinal c.g. of the contents by using numerical integration (e.g., Simpson's first rule) by figuring the area at a series of equally spaced cross sections and then calculating moments from one end of the cylinder. The final result should give you the volume of the contents and the first moment about one end, and you can calculate the c.g. by dividing the moment by the volume.
     
  6. Apr 25, 2014 #5
     
  7. Apr 25, 2014 #6

    SteamKing

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    Yes, in this attachment:

    http://www.pomorci.com/Skole/Stabilitet/STABILITY 10,11,12.pdf

    You'll also want some info about calculating the areas of the various circular segments:

    http://en.wikipedia.org/wiki/Circular_segment

    In your calculation, the distance of the cross section from one end of the cylinder will be x, and the area of the cross section of the contents will be y, which is also called the ordinate. You'll want to create a table of these x and y values and then apply the Simpson's multipliers and the ordinate values. This type of calculation works well using a spreadsheet program like Excel.

    Pay close attention to the end of the cylinder where the depth of the contents gradually vanishes. You may want to use more closely spaced cross sections in this region to improve accuracy.
     
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