Center of Mass question (help)?

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To find the x-coordinate of the center of mass (CoM) of a human leg modeled as two uniform segments, the calculations should consider the mass and position of both the upper and lower leg. For a leg length of 0.92 m, the upper leg's CoM is at 0.46 m and the lower leg's CoM is at 0.69 m from the hip joint. The formula for CoM is ∑ m*x/∑ m, which requires the masses and their respective distances from the reference point. The incorrect calculation of 0.35 m likely stems from not properly accounting for the positions of both segments and their respective masses. Correctly applying the CoM formula will yield the accurate x-coordinate for both the horizontal and bent configurations.
driftk
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I tried this problem but only managed to somewhat understand Part A. But that answer is wrong as well, so can someone guide me through steps of finding the answer: Thank you.

To keep the calculations fairly simple, but still reasonable, we shall model a human leg that is 0.92 m long (measured from the hip joint) by assuming that the upper leg and the lower leg (which includes the foot) have equal lengths and that each of them is uniform. For a 70.0 Kg person, the mass of the upper leg would be 8.60 Kg, while that of the lower leg (including the foot) would be 5.25 Kg.

A. Find the x-coordinate of the center of mass of this leg, relative to the hip joint, if it is stretched out horizontally.

- i got 0.35 as my answer but it was wrong. My method was this: (5.25*0.92)/ total mass of 13.85. What am I doing wrong?

B. Find the x-coordinate of the center of mass of this leg, relative to the hip joint, if it is bent at the knee to form a right angle with the upper leg remaining horizontal.
 
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driftk said:
I tried this problem but only managed to somewhat understand Part A. But that answer is wrong as well, so can someone guide me through steps of finding the answer: Thank you.

To keep the calculations fairly simple, but still reasonable, we shall model a human leg that is 0.92 m long (measured from the hip joint) by assuming that the upper leg and the lower leg (which includes the foot) have equal lengths and that each of them is uniform. For a 70.0 Kg person, the mass of the upper leg would be 8.60 Kg, while that of the lower leg (including the foot) would be 5.25 Kg.

A. Find the x-coordinate of the center of mass of this leg, relative to the hip joint, if it is stretched out horizontally.

- i got 0.35 as my answer but it was wrong. My method was this: (5.25*0.92)/ total mass of 13.85. What am I doing wrong?

B. Find the x-coordinate of the center of mass of this leg, relative to the hip joint, if it is bent at the knee to form a right angle with the upper leg remaining horizontal.

The Center of Mass is the ∑ m*x/ ∑ m

What they want you to do is calculate the CoM using both the two leg parts, upper and lower. Since they say that each piece is uniform, then you can assume that the CoM's of each piece are located half way on each part.
 
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