Centre of gravity of this system of particles

AI Thread Summary
To find the center of gravity of a system of particles, use a weighted average of their positions. For the given masses, the x-coordinate is calculated as (4*0 + 6*30 + 8*30) / (4 + 6 + 8), resulting in 23.33. The y-coordinate is (4*0 + 6*0 + 8*(-14)) / (4 + 6 + 8), yielding -6.22. The negative y-coordinate indicates the center of gravity is below the reference point. This method effectively determines the center of gravity based on the distribution of mass.
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Homework Statement



Find the centre of gravity of this system of particles

Homework Equations



attached image showing diagram

http://www.zshare.net/image/7209360586277b98/

The Attempt at a Solution



Taking moments about a, 4*0+6*30 = 184 then not sure

Any help is greatly appreciated

Thanks in advance
 
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Don't worry about moments- take a "weighted" average of the components. Taking the 4 kg mass on the left to be at (0, 0), the 6 kg mass is at (30, 0) and the 8 kg mass at (30, -14). The x-coordinate of the center of mass will be at
\frac{4(0)+ 6(30)+ 8(30)}{4+ 6+ 8}
and the y-coordinate will be
\frac{4(0)+ 6(0)+ 8(-14)}{4+ 6+ 8}
 
Thanks for the reply, ok so I get 23.33 for x and -6.22 for y,

Providing I have calculated the sums correctly,
the minus is throwing me off in locating the centre?

Thanks again!
 
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