Centripetal Acceleration and period of rotation

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SUMMARY

The discussion focuses on calculating the period of rotation required for a volunteer in a "g-suit" to achieve specific centripetal accelerations of 3.7g and 10g while rotating in a horizontal circle with a radius of 7.7m. The key equations used include centripetal acceleration, a = v²/r, and the relationship between velocity and period, v = 2πr/T. The derived formula for the period of rotation is T = 2π√(r/a), allowing for the calculation of the period based on the desired acceleration.

PREREQUISITES
  • Centripetal acceleration concepts
  • Understanding of circular motion equations
  • Basic algebra for solving equations
  • Knowledge of gravitational acceleration (g = 9.8 m/s²)
NEXT STEPS
  • Calculate the period of rotation for different values of centripetal acceleration using T = 2π√(r/a).
  • Explore the implications of varying radius on centripetal acceleration and period.
  • Investigate the effects of increased gravitational forces on human tolerance during circular motion.
  • Learn about the applications of "g-suits" in aviation and space travel.
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Physics students, educators, and professionals interested in mechanics, circular motion, and applications of centripetal acceleration in real-world scenarios.

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Homework Statement



In a test of a “g -suit,” a volunteer is rotated in a horizontal circle of radius 7.7m.

What must the period of rotation be so that the centripetal acceleration has a magnitude of 3.7g ?

What must the period of rotation be so that the centripetal acceleration has a magnitude of 10g?



Homework Equations


F=ma
w=ma
4pi^2r/T

The Attempt at a Solution



Ok I started by converting 3.7g, by doing this 9.8*3.7 = 36.26

4pi^2(7.7)/ 36.26

but it is wrong, how would I solve this?
 
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4pi^2r/T

This isn't right, check the units. It's supposed to be acceleration, right? Did you derive it yourself?
 
I've been told it has something to do with the equation, although I don't think I am using properly.

what would you do in the following situation?
 
Well, start with the equation for centripetal acceleration, a = v^2/r. You need to relate it to the period. You can do that by the velocity term. What's a way to express the velocity of an object moving in a circle?
 
velocity would be distance/time.

Circumference = 2*pi*Radius

v=2pir/t ?
 
That's right. Now put that together with the a=v^2/r and you should come up with the equation you need.
 
a = 4pi^2r / t^2

?
 
Yes. So solve that for t and use it to find the period.
 
ok got it. thank you
 

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