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SamitC
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Because in Δt, the velocity changes from v0 to v. And for small change in time this can be equal to the distance traveled because of the triangle similarities. That is what the assumption is behind the effort. Can you pls. elaborate where you find something wrong or missing ?Doc Al said:
A change in velocity cannot equal a distance. You can use similar triangles: ##\frac{\Delta v}{v} = \frac{\Delta x}{r}##. Use that and you can easily derive the formula.SamitC said:
I got it now. It has to be the ratio...Thanks a lotDoc Al said:
The formula for centripetal acceleration is given by a = v^2/r, where a is the centripetal acceleration, v is the velocity of the object, and r is the radius of the circular motion.
The centripetal acceleration formula is derived from the equation for acceleration, a = ∆v/∆t, and the definition of centripetal acceleration, a = v^2/r. By combining these equations, we can derive the formula a = v^2/r.
The centripetal acceleration formula is significant because it allows us to calculate the acceleration of an object moving in a circular path. This is important in many scientific fields, such as physics, engineering, and astronomy.
Yes, the centripetal acceleration formula can be used for any type of circular motion, as long as the motion is uniform and the radius of the circle is known.
The centripetal acceleration formula is related to Newton's laws of motion in that it is a specific application of Newton's second law, F = ma. In circular motion, the centripetal force is the force that causes the object to move in a circular path, and the centripetal acceleration is the result of this force acting on the object.
