Centripetal Acceleration & Frictional Force

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SUMMARY

The maximum speed a light truck can maintain while navigating a curve is determined by the centripetal force equation, Fc = m(v^2/r). Given that the truck can travel at 32.0 m/s on a curve with a radius of 150 m, it can achieve a maximum speed of 22.6 m/s on a tighter curve with a radius of 75.0 m. This conclusion is based on the assumption that the static friction force remains constant across both curves, allowing for the mass to be canceled out in the calculations.

PREREQUISITES
  • Understanding of centripetal force and its equation (Fc = m(v^2/r))
  • Knowledge of static friction and its role in circular motion
  • Ability to manipulate algebraic equations for solving variables
  • Familiarity with free body diagrams to visualize forces
NEXT STEPS
  • Study the effects of varying radius on centripetal acceleration
  • Learn about the role of friction in different road conditions
  • Explore advanced topics in dynamics, such as angular momentum
  • Investigate the impact of vehicle mass on maximum speed in circular motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators teaching these concepts in a classroom setting.

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Homework Statement


A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 32.0 m/s. With what maximum speed can it go around a curve having a radius of 75.0 m?

Homework Equations


Fc = m(v^2/r)

Fc = net centripetal force
m = mass
v = tangenital speed
r = radius

The Attempt at a Solution



The answer I got is what is in the back of my book, but I am unsure if I took the right path to get to the answer and if my reasoning is sound. Any feedback would be greatly appreciated!

In a free body diagram of this problem the only force acting in the radial direction is the force of static friction keeping the car on the road. Although the problem does not state this directly, I'm assuming that the truck is taking the second curve of radius 75.0 m under the same road conditions as the first curve. If this is true, then the net centripetal force would be equal in both curves (the force of static friction is the same on both curves).

If Fc = m(v^2/r) and Fc is the same in both situations, then I can set m(v^2/r) of the first curve equal to the second, getting:
m(v1^2/r1) = m(v2^2/r2)
where v1 = tangenital velocity of curve 1 = 32.0 m/s
r1 = radius of curve 1 = 150 m
v2 = unknown solving for
r2 = radius of curve 2 = 75 m

I can cancel out mass, and get:
32^2/150 = v2^2/75

For a solution, I get v2 = 22.6 m/s.
 
Last edited:
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Yes both your method and reasoning are correct.
 

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