1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Centripetal Acceleration

  1. Feb 17, 2009 #1
    1. The problem statement, all variables and given/known data

    What would Earth's rotation period have to be for objects on the equator to have a centripetal acceleration equal to 9.8 m/s^2?

    ____ min


    2. Relevant equations

    Centripetal acceleration is equal to velocity * (2PI/T),
    where T is the period in seconds.




    3. The attempt at a solution

    I set centripetal acceleration equal to 9.8m/s^2 and solved for T. Then I took T and divided it by 60 so I could get the answer in minutes. I came out with 4.97 min which Webassign says is incorrect. Any ideas?
     
    Last edited: Feb 17, 2009
  2. jcsd
  3. Feb 17, 2009 #2

    LowlyPion

    User Avatar
    Homework Helper

    One way to look at it is that if the object is not to fall into the center then calculate the orbit about a mass of Earth at 1 earth radius.

    So what is the period of such an orbit?

    V2/R = GM/R2 = ω2R

    ω2 = GM/R3 = (2π /T)2

    T = 2π*(R3/GM)1/2
     
  4. Feb 17, 2009 #3
    What does GM stand for?
     
  5. Feb 17, 2009 #4

    LowlyPion

    User Avatar
    Homework Helper

    That's sometimes written as μ which is the standard gravitational parameter for earth.

    It is the product of earth's mass and the Universal Gravitational constant.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Centripetal Acceleration
Loading...