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I wondered what would happen to a steel mass that was spun around an axis in a circular motion and then suddenly released. What would happen to the velocity of the mass? Would it be the same as the tangent velocity? What about the direction of the mass as it heads off in in a new direction. After some number crunching I found the new velocity of the mass would be:

[tex] v = \sqrt {2 V_t ^2 [/tex]

Where [tex] {V_t [/tex] is the tangent velocity.

Not only that but the kinetic energy of the mass as it rotates about the axis is

[tex] {m V_t^2 [/tex]

exactly twice what you would expect

The most amazing thing is that the new velocity is higher than the tangent velocity and at the moment of release of the mass, it did not accelerate to the new speed!!

is the math correct?

[tex] v = \sqrt {2 V_t ^2 [/tex]

Where [tex] {V_t [/tex] is the tangent velocity.

Not only that but the kinetic energy of the mass as it rotates about the axis is

[tex] {m V_t^2 [/tex]

exactly twice what you would expect

The most amazing thing is that the new velocity is higher than the tangent velocity and at the moment of release of the mass, it did not accelerate to the new speed!!

is the math correct?

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