Centripetal force and acceleration

AI Thread Summary
To calculate the Moon's acceleration, the period of 27.3 days must be converted into seconds. The relevant equations for centripetal acceleration are a = v^2/r and a = 4(pi)^2r/T^2, but the second equation's inclusion of mass (m) is unnecessary for this problem. After conversion, using the second equation yields an acceleration of approximately 2.72 x 10^-3 m/s². Understanding unit conversion and the correct application of formulas is crucial in solving such physics problems.
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Homework Statement


The moon takes 27.3 days to circle Earth and its centre is located 3.84 x 108 m from the centre of Earth. What is the Moon’s acceleration?


Homework Equations


a=v^2/r, a=4(pi)^2mr/T^2


The Attempt at a Solution


i don't know how to answer this question becuase i don't know what I am suppossed to do with the 27.3 days.
 
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Your equations look good except for the "m" in the second equation. Where did that come from?

Anyways, the units of acceleration is the meter per second per second, m/(s^2). You must convert the days to seconds. This is a common procedure for many intro physics problems.
 
so then i would just use the second equation i provided(excluding the m) plug everything in and get an answer of 2.72 x 10^-3 m/s2??
 
Yups
 
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