Change in density due to thermal expansion

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SUMMARY

The discussion focuses on the mathematical proof of how density changes with thermal expansion, specifically transitioning from the equation Δρ=m/ΔV to Δρ/ρ= -3(ΔL/L). Key equations involved include V=(1+βΔT)Vi and L=(1+αΔT)Li. Participants clarify that the volume of an object expands cubically with temperature changes, leading to the conclusion that the density decreases as temperature increases, hence the negative sign in the equation. The correct interpretation of the algebra shows that Δρ/ρ = -3(ΔL/L) is indeed valid.

PREREQUISITES
  • Understanding of thermal expansion coefficients (α and β)
  • Familiarity with density and volume equations
  • Basic algebra and manipulation of equations
  • Knowledge of cubic volume expansion
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  • Study the derivation of thermal expansion equations
  • Learn about the implications of negative density change
  • Explore the relationship between temperature and material properties
  • Investigate real-world applications of thermal expansion in engineering
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Students in physics or engineering, educators teaching thermal dynamics, and professionals involved in material science or mechanical engineering.

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Homework Statement


I want to find the mathematical proof to show that the density of an object changes with thermal expansion. My professor showed this in class and it was horribly wrong because he let a few things out. The book I'm reading showed it in 4 steps and left out a lot of the crucial parts. I've been working on this for a few days.

How do I go from, Δρ=m/ΔV, to Δρ/ρ= -3(ΔL/L) ?
I think these are the relevant equations:
V=(1+βΔT)Vi
L=(1+αΔT)Li
V=m/ρ

The Attempt at a Solution


This is how I got it but I don't think it's correct: m.imgur.com/a/ZOfCp
 
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My friend, don't struggle so much for it.

You know that ρ=m/V.
Let ρ°=m/V°.
Then V°= V( 1+γΔT) where γ=3α.
Put that into the equation above, divide by ρ, subtract 1. You have your answer.
 
empty_set said:

Homework Statement


I want to find the mathematical proof to show that the density of an object changes with thermal expansion. My professor showed this in class and it was horribly wrong because he let a few things out. The book I'm reading showed it in 4 steps and left out a lot of the crucial parts. I've been working on this for a few days.

How do I go from, Δρ=m/ΔV, to Δρ/ρ= -3(ΔL/L) ?
I think these are the relevant equations:
V=(1+βΔT)Vi
L=(1+αΔT)Li
V=m/ρ

The Attempt at a Solution


This is how I got it but I don't think it's correct: m.imgur.com/a/ZOfCp
It isn't clear what you did. I suggest doing the analysis on a cube. $$V_0=L_0^3$$
$$V=L^3=[L_0(1+\alpha \Delta T)]^3$$
and neglect non-linear terms in ##\Delta T##.
 
For both of those methods I got Δρ/ρ = 3(ΔL/L). Would the negative be implied or is my algebra wrong?
 
empty_set said:
For both of those methods I got Δρ/ρ = 3(ΔL/L). Would the negative be implied or is my algebra wrong?
There should be a minus sign in this equation.
 
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Likes   Reactions: CrazyNinja
Your algebra is wrong. My method WILL give a minus sign inherently. Check again. You probably got confused with the ρ and ρ°.
 

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