Change in Momentum using Vectors

AI Thread Summary
A force F = (2ti + 3t^2j) N acts on an object in the xy plane, and the task is to find the change in momentum from t=0 to t=2. The magnitude of the force is derived as (4t^2 + 9t^4)^(1/2), leading to the expression for change in momentum as delta p = 2t(4 + 9t^2)^(1/2). To find the total change in momentum, integration of the force over the specified time interval is necessary due to its time-dependent nature. The integration yields a change in momentum of 4i + 8j. Understanding this process is linked to Newton's second law, which relates force and momentum change.
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Homework Statement


A force F = (2ti + 3t^2j) N acts on an object moving in the xy plane. Find the magnitude of change in momentum of the object in time interval t=0 to t=2
(The bold ones are vectors)

Homework Equations


Ft=change in momentum

The Attempt at a Solution


magnitude of F = (4t^2 + 9t^4)^(1/2)
taking t^2 common:
t(4+9t^2)^(1/2)
Ft=delta p
so, delta p = 2t(4 + 9t^2 ) ^ (1/2)

But the answer doesn't have ts in it.
 
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Have you learned calculus? The force is time-dependent, so you will have to perform an integration to find out the total change in momentum over the time interval.
 
Fightfish said:
Have you learned calculus? The force is time-dependent, so you will have to perform an integration to find out the total change in momentum over the time interval.
I have learned it. But have never actually used it in physics.
So I integrate F?
Like:
Integration of 2ti+3t^2 j
is t^2i + t^3j
with the limits 0 and 2
Then,
4i + 8j is the change in p
 
Yes. You can understand the integration process by looking at Newton's second law, which states that \vec{F} = \frac{d\vec{p}}{dt}, and so this immediately results in \Delta p = \int_{t_0}^{t_f}\vec{F} dt
 
Fightfish said:
Yes. You can understand the integration process by looking at Newton's second law, which states that \vec{F} = \frac{d\vec{p}}{dt}, and so this immediately results in \Delta p = \int_{t_0}^{t_f}\vec{F} dt
Thank you!
 
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