Change of variables, transformations, reversibility

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SUMMARY

The discussion centers on the theorem regarding the reversibility of variable transformations, specifically when the Jacobian of the transformation is nonzero at a point (u0, v0). The transformation defined by x = uv and y = u² - v² leads to intersections of level curves in the u-v plane, indicating that the transformation is not one-to-one. The user struggles to find the coordinates (u, v) for specific values (x0, y0) and expresses difficulty with similar problems involving higher-degree polynomials.

PREREQUISITES
  • Understanding of Jacobian matrices and their role in transformations.
  • Familiarity with level curves and their intersections in multivariable calculus.
  • Knowledge of polynomial equations, particularly third-degree polynomials.
  • Graphing techniques for visualizing transformations in the u-v plane.
NEXT STEPS
  • Study the properties of Jacobians in multivariable calculus.
  • Learn how to graph level curves and analyze their intersections.
  • Research methods for solving third-degree polynomial equations.
  • Explore examples of non-one-to-one transformations and their implications.
USEFUL FOR

Students and educators in multivariable calculus, mathematicians dealing with transformations, and anyone interested in understanding the implications of Jacobians in variable changes.

Jamin2112
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Homework Statement



Theorem. The change of variables is reversible near (u0,v0) (with continuous partial derivatives for the reverse functions) if and only if the Jacobian of the transformation is nonzero at (u0,v0).

1. Consider the change of variables x=x(u,v)=uv and y=y(u,v)=u2-v2.

(a). Find the coordinates (u,v) that go to a common value (x0,y0) under than change of variables. (That is, find the points of intersection of the level curves x0=x(u,v) and y0=y(u,v) in the u-v plane.) Generally, this transformation transforms how many points in the u-v plane to an image point in the x-y plane?

Homework Equations

The theorem, I suppose.

The Attempt at a Solution



So, I want to see what happens when I fix x and y. Let's say (x,y)=(x0,y0).

x0=uv
y0=u2-v2.

Graphing this in the u-v plane would look like a hyperbola, v=x0/u, that intersects a square root thingy, v= +/- √(u2-y0). The two curves should intersect at 2 points, meaning that we don't have a 1-1 transformation. But I can't find the coordinates (u,v) of this intersection. I can simplify it to x02=u2(u2-y0), but can't solve for u from there.

I have this problem on every other problem on this assignment. For example, the next problem has x=uv, y=u3+y3. How do I solve for u,v? Seems like I would need to know the formula for solving a 3rd degree polynomial. Or is there an easier way?

Thanks in advance. Expound as much as possible.
 
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