Changing places in canoe - find mass

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SUMMARY

In the discussion, Ricardo (mass 82 kg) and Carmelita (unknown mass) exchange seats in a 38 kg canoe, resulting in the canoe moving 58.4 cm horizontally. The problem is solved using the principle of conservation of the center of mass, which states that the center of mass of the system must remain stationary when no external forces act on it. By setting the initial and final positions of the center of mass equal, the mass of Carmelita can be calculated as 62 kg.

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Ricardo, of mass 82 kg, and Carmelita, who is lighter, are enjoying Lake Merced at dusk in a 38 kg canoe. When the canoe is at rest in the placid water, they exchange seats, which are 3.1 m apart and symmetrically located with respect to the canoe's center. Ricardo notices that the canoe moves 58.4 cm horizontally relative to a pier post during the exchange and calculates Carmelita's mass. What is it?

Thankz to anyone who can show how to solve this really appreciate it.
 
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Think center of mass. There is no net force acting on the system of Ricardo+Carlita+boat... so the center of mass must remain motionless.

Call carlita's mass m.

Take a fixed axis from which you measure the position of the center of mass...

what is the initial position of the center of mass from this axis in terms of m?

what is the final position of the center of mass from this axis in terms of m (remember that the boat moves 58.4cm)?

initial position = final position...
 

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