Charge distribution in a conducting sphere

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SUMMARY

The discussion focuses on the charge distribution \(\rho(r,t)\) in a conducting sphere with constant permittivity \(\epsilon\) and conductivity \(\sigma\). Participants emphasize the application of Gauss' Law and Ohm's Law to derive the electric field and current density. A consensus emerges that, as time progresses, all charge will reside on the surface of the sphere, although complexities such as skin depth and diffusion are acknowledged. The continuity equation is suggested as a potential tool for solving the problem.

PREREQUISITES
  • Understanding of Gauss' Law in electrostatics
  • Familiarity with Ohm's Law in differential form
  • Knowledge of charge density and current density concepts
  • Basic principles of diffusion in conductive materials
NEXT STEPS
  • Explore the continuity equation in electromagnetic theory
  • Study the effects of skin depth in conductors
  • Investigate diffusion problems with spherical symmetry
  • Learn about time-reversal techniques in solving differential equations
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Physics students, electrical engineers, and researchers focused on electromagnetic theory and charge distribution in conductive materials.

Plantis
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Homework Statement



At time t = 0 a charge distribution \rho(r) exists within an idealized homogeneous conductor whose permitivity \epsilon and conductivity \sigma are constant. Obtain \rho(r,t) for subsequent times.


Homework Equations



Maxwell's equations = Gauss' Equation + Ohm's law in Differential form

The Attempt at a Solution



By using Gauss' law I can find how an electric field depend from radius. After it I can use Ohm's law to find current density through the surface of a sphere of radius R. Then I can find quantity of charges that leave the sphere of radius R per unit time. See attachment.

q - the number of the charge coming out of the sphere of radius r.
 

Attachments

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I wonder if it would help to first solve a simpler problem, say one where the charge density was uniform, rho(r) = constant inside the sphere. You can almost picture the resulting current, it will be radial and can easily figure out rho(r,t) for t large, all the charge will lie on the surface? Good luck, challenging problem!
 
Spinnor said:
I wonder if it would help to first solve a simpler problem, say one where the charge density was uniform, rho(r) = constant inside the sphere. You can almost picture the resulting current, it will be radial and can easily figure out rho(r,t) for t large, all the charge will lie on the surface? Good luck, challenging problem!

So what? it is obviously. In case t large all charge will be on the surface. I understand that there will be radial current in proposed situation by you. I understand what happen inside the sphere. But, I can not solve the problem.I think that my solution is correct. However, It need to be checked.
 
Last edited:
Plantis said:
So what? it is obviously. In case t large all charge will be on the surface. I understand that there will be radial current in proposed situation by you. I understand what happen inside the sphere. But, I can not solve the problem.

Could you solve the easier problem?
 
Spinnor said:
Could you solve the easier problem?

I do not understand you.
 
Plantis said:
I do not understand you.

When you are stuck and getting nowhere I thought it was good practice to step back and solve an easier problem.

Anyway does the continuity equation help to solve your problem? You have not used it.

Good luck.
 
Plantis said:
1. The problem statement...


Why should there be a flux of electrons from the surface of the sphere?
Do you mean you are creating an arbitrary Gaussian surface within the sphere and figuring out the current density through that surface?

You can treat this as a diffusion problem with spherical symmetry and the classical assumption that the charge must reside on the surface after a very long time.
A trickier consideration is that the charge will not in fact reside completely on the surface, but will have a skin depth.
How does that affect your solution?

In any event, there is a key symmetry that will make the solution obvious... and also see if working the problem in time reversal helps.
 

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