Charged capacitors in series and both ends of wire connected

AI Thread Summary
When two capacitors are connected in series, they share the same charge, which can be calculated based on the total voltage and their capacitances. In this case, a 3 microfarad and a 6 microfarad capacitor connected to a 10V battery will have a specific charge distribution. Once the battery is disconnected and the loose ends are connected, the potential difference across the capacitors will not be zero; instead, the charge will redistribute between them. This redistribution does not create a short circuit, but rather allows the capacitors to balance their voltages. Ultimately, the potential difference will stabilize at a value determined by the series configuration and the initial charge.
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Two Capacitors are connected in series (3 microfarad and 6 microfarad) with Vab=10V. Battery is disconnected and the loose ends of wire are connected. What happens to the potential difference?Would it be zero..charge? I can't figure it out...sounds like a short circuit?
 
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(i) First, determine the charge the battery puts on each capacitor. The charge added to one capacitor = the charge added to the other, since they are in series.

(ii) ...
 

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