Charged coaxial cable - Charge distribution?

AI Thread Summary
The discussion revolves around determining the charge distribution in a coaxial cable system consisting of an infinitely long wire and a coaxial conducting cylinder. The wire has a linear charge density of +u, while the cylinder has a linear charge density of +2u. It is established that the charge on the central wire is distributed on its outer surface, while the inner surface of the conducting cylinder must have a linear charge density of -u to maintain an electric field of zero within the conductor. Consequently, the outer surface of the cylinder ends up with a linear charge density of +3u. This understanding is confirmed as correct through the application of Gauss's Law.
quanticism
Messages
29
Reaction score
3

Homework Statement



Say we have an infinitely long wire with radius r1 with a linear charge density +u and we have a coaxial conducting cylinder with radius r2->r3 and a linear charge density of +2u.

http://img573.imageshack.us/img573/3419/coaxialcable.png"

Now the overall aim of the question is to find the electric field at various points away from the centre.

ie. r<r1, r1<r<r2, r2<r<r3, r>3

2. The attempt at a solution

But before I can do that, I need to know how the charges are distributed in the two conductors.

Now we know that a conductor in electrostatic equilibrium has these properties:

1) The electric field is zero everywhere inside the conductor (whether hollow or solid)

2)If the conductor is isolated and carries a charge, the charge resides on the surface.

I can't seem to visualise how the charges will distribute. My initial impression was that it would do something like this but now I'm not too sure.

http://img221.imageshack.us/img221/3233/chargedistribution.png"

Any nudges in the right direction would be nice.
 
Last edited by a moderator:
Physics news on Phys.org
I think I understand how the charges distribute now.

The central wire must have the net charge distributed on the outer surface (at r=r1). So the linear charge density along this surface is +u.

The inner surface of the conducting cylinder (r=r2) must have a linear charge distribution of -u. This is to ensure that the electric field from r2->r3 is zero (shown using Gauss's Law).

The question said the conducting cylinder had a linear charge density of +2u so that means the outer surface of the cylinder (r=r3) has a linear charge density of +3u.

Is this correct?
 
Yes.

ehild
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top