Charging 10 1F Capacitors: Output Voltage and Capacitance?

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SUMMARY

Charging ten 1F capacitors in series at 10 volts results in each capacitor having 1 volt across it, leading to a total capacitance of 0.1F for the series configuration. When these capacitors are discharged in parallel, they collectively provide 10C of charge at 1 volt, maintaining a capacitance of 1F. The discussion clarifies that the term "charged capacitance" is misleading, as capacitance is a fixed property of the capacitor, not dependent on charge.

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Idea04
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Can you tell me if I'm right with this. If you charge ten 1F capacitors in series at 10 volts. Each capacitor has a voltage of 1 volt and a charged capacitance of 0.1F. So if you discharged the ten capacitors in parallel the output would be equal to 1F of capacitance charge and 1 volt. or would the output be 10 volts and 1F of charged capacitance.
 
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Do we have a problem with nomenclature here?
"a charged capacitance of 0.1F" ? Not sure what that means as charge is in Coulombs (C).
A 1F capacitor will always have a capacitance of 1F - surely.
All ten capacitors will have the same charge (1C, assuming they really are identical) and 1V across it, so the set in parallel will have 10C of charge, total, and 1V across them.
The ten, in series, will have a capacitance of 0.1F (whatever the charge).
 
Most likely this can only be answered by an "old timer". I am making measurements on an uA709 op amp (metal can). I would like to calculate the frequency rolloff curves (I can measure them). I assume the compensation is via the miller effect. To do the calculations I would need to know the gain of the transistors and the effective resistance seen at the compensation terminals, not including the values I put there. Anyone know those values?

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