Checking the effect an operator has on a state

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The discussion centers on the mathematical operation involving a rotation operator \( R \) applied to a quantum state \( \rho \). The correct transformation is given by \( \rho' = R\rho R^{\dagger} \), which ensures that the resulting state \( \rho' \) remains valid within the framework of quantum mechanics. This approach is necessary because it preserves the properties of the quantum state under the action of a unitary operator, as highlighted in the referenced notes, particularly on slides 5 and 8.

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I've been reading these notes: http://www.vcpc.univie.ac.at/~ian/hotlist/qc/talks/bloch-sphere-rotations.pdf
And on slide 11, to check what the rotation operator is doing, the state is pre- and post-multiplied by the operator so that the calculation performed is
##\rho' = R\rho R^{\dagger}##
Why do we need to do that and not just
##\rho' = R\rho##?
Thanks for any help! :)
 
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In the same link, take a look at how ρ is defined(slide #5) and how it transforms under the action of a Unitary operator(slide #8). Considering R being Unitary, the answer to your question should be straightforward.
 
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