Checkpoint: Conservative Forces And Potential Energy

AI Thread Summary
The discussion focuses on comparing the kinetic energy of two identical objects released from different heights above the Earth's surface. In Case 1, an object is released from a height of 1 Earth radius, resulting in kinetic energy K1, while in Case 2, an object is released from 2 Earth radii, yielding kinetic energy K2. The conservation of energy principle indicates that K2 is half of K1 due to the relationship between gravitational potential energy and kinetic energy. The calculations show that K1 and K2 are inversely related to their respective distances from the Earth's center. This analysis highlights the impact of height on kinetic energy just before impact.
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Homework Statement



Consider two identical objects released from rest high above the surface of the Earth (neglect air resistance for this question).

In Case 1 we release an object from a height above the surface of the Earth equal to 1 Earth radius, and we measure its kinetic energy just before it hits the Earth to be K1.
In Case 2 we release an object from a height above the surface of the Earth equal to 2 Earth radii, and we measure its kinetic energy just before it hits the Earth to be K2.
1) Compare the kinetic energy of the two objects just before they hit the surface of the earth.


Homework Equations



Ugrav= -G*me*mb/ (R-earth)
KE= 1/2mv^2
conservation of energy- k+u=0

The Attempt at a Solution



K=-U
1/2mv^2 = Gmemb/r-earth

K1= 1/2mv^2
K2= 1/4mv^2

Wouldn't the K2= 1/2(k1) due to the conservation of mechanical energy. The radius of the Earth is inversely proportional to the kinetic energy
 
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