4Cu + O2 --> What is the name of the compound ?

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The reaction 4Cu + O2 produces the ionic compound copper(I) oxide, represented as Cu2O. The balanced equation for the reaction is 4Cu + O2 = 2Cu2O, resulting in the formation of 2 moles of the compound. Copper is more likely to oxidize to the +1 state due to the lower energy required for the first electron removal compared to the second. Additionally, copper(I) oxide has a lower enthalpy of formation than copper(II) oxide, making it the more energetically favorable product. Understanding these factors clarifies why copper(I) oxide is the correct answer.
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The below reaction gives one ionic compound as a product.

4Cu + O2 -->

What is the name of the compound ?

An example of the correct answer format would be lead(II) nitrate note the space

Its going to be copper(I) oxide right, but I don't understand why?

Also How many moles of the ionic compound are produced for the above reaction , would it be 4?
 
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First write and balance the complete reaction. There can be no discussion of the second part before you do this.
 
Gokul43201 said:
First write and balance the complete reaction. There can be no discussion of the second part before you do this.

Isnt it

4Cu + O2= 2Cu2O

so it would be 2 moles, but why is it copper I oxide, not copper II oxide
 
It is easier to oxidize somethingto +1 (usually), than it is to oxidize it to +2. Taking that first electron away isn't so tough, but the second requires much more energy.
Also, Copper (I) Oxide has a lower enthalpy of formation than Copper (II) Oxide, so it is more energy favorable for copper to oxidize to +1 than go all the way to +2.
 
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