- #1

- 8

- 0

the melting temperature of Sn, Tm, Sn = 505 [K]

the enthalpy of fusion of Sn, hfus, Sn = 7070 [J/mol]

the heat capacity of liquid Sn, Cp, Sn(l) = 34.7 – 9.2 x10-3 T [J / (mol K)]

the heat capacity of solid Sn, Cp, Sn(s) = 18.5 + 2.6 x 10-2 T [J / (mol K)]

(a) Briefly explain what will happen to the supercooled liquid tin.

(b) Calculate the fraction of liquid tin which spontaneously freezes. Provide a clearly labeled

hypothetical path used in your calculation. State any assumption(s) you make.

I know (a), i'm just unsure how to draw a hypothetical path and unsure where to even start the calculation, any help is appreciated