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Chemistry - analyzing equations

  1. Jul 17, 2008 #1
    1. The problem statement, all variables and given/known data
    4FeCr2O7 + 8K2CO3 + O2 --> 2Fe2O3 + 8K2CrO4 + 8CO[sub2[/sub]

    How many grams of iron (II) dichromate are required to produce 44.0 grams of carbon dioxide?


    2. Relevant equations



    3. The attempt at a solution

    79.925 grams of iron (II) dichromate
     
  2. jcsd
  3. Jul 17, 2008 #2

    Borek

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    Staff: Mentor

    Too low. Show your work.

    Strange reaction and strange reactant though. If you ask me, there is no such thing as iron (II) dichromate.
     
  4. Jul 17, 2008 #3
    Nevermind my first answer, I misinterpreted the problem, this is my new answer:

    Since it takes takes 4 moles of iron (II) dichromate to produce 8 moles of carbon dioxide, it would take 0.5 moles of iron (II) dichromate to produce 1 mole of carbon dioxide (1 mole of CO2 = 44 g). And 0.5 moles of iron (II) dichromate = 109.92 grams of iron (II) dichromate (answer).

    -- I don't really know what I'm doing btw; these are questions from my pre-AP Chem summer assignment and I'm bookless and haven't done any chemistry for about 1 1/2 years.
     
  5. Jul 18, 2008 #4

    Borek

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    Staff: Mentor

    Your approach is OK, just numbers are wrong. What have you used for molar mass of iron (II) dichromate?
     
  6. Jul 18, 2008 #5
    molar mass of iron (II) dichromate = 271.85 g

    271.85/2 = 135.93 g... nevermind my other answer, is 135.93 g correct?
     
  7. Jul 21, 2008 #6

    Borek

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    135.9 g is OK. Sorry for the late answer.
     
  8. Jul 24, 2008 #7
    molar mass 4FeCr2O7 = 1087.4 g

    molar mass 8CO2 = 352.08 g

    1087.4/352.08 = x/44 ~ x = 135.9 g

    ^ Is it possible to use proportions for these type of problems?
     
  9. Jul 24, 2008 #8

    Borek

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    Staff: Mentor

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