Solving Chemistry Questions: Mercury (II) Sulfide HgS

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Mercury (II) sulfide (HgS) exists in two forms: red vermillion and black, with color differences attributed to band gap transitions (BGT). The red form is believed to have a larger band gap compared to the black form. In weak field octahedral complexes, the d-d transitions are more likely to produce a blue color due to the absorption of light in the red spectrum. This is based on the principle that the observed color is complementary to the absorbed frequency. Understanding these concepts is crucial for solving related chemistry questions effectively.
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Homework Statement



Mercury (II) sulfide. HgS, occurs in two forms. One is red pigment known as vermillion; the other is black. In both, the color is due to band gap transitions (BGT). Which form has the larger band gap?



Homework Equations



In weak field octahedral complexes, DELTA is relatively small. Are the d-d transitions in these complexes more likely to make the complex red or blue?



The Attempt at a Solution



for my first question I believe the answer is Red.
for my second question I believe the answer is blue.
 
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Sounds like good logic. Remember that the color you see is the complimentary color of the absorbed frequency.

From Wiki: (crystal field theory)

λ absorbed versus colour observed
400nm Violet absorbed, Green-yellow observed (λ 560nm)
450nm Blue absorbed, Yellow observed (λ 600nm)
490nm Blue-green absorbed, Red observed (λ 620nm)
570nm Yellow-green absorbed, Violet observed (λ 410nm)
580nm Yellow absorbed, Dark blue observed (λ 430nm)
600nm Orange absorbed, Blue observed (λ 450nm)
650nm Red absorbed, Green observed (λ 520nm)
 
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