Cherry Pickr Tippng Angle & Potential Energy Req To Tip

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Discussion Overview

The discussion revolves around calculating the potential energy required to tip a cherry picker on semi-submersible rigs during various sea states. Participants explore the mechanics of tipping, including the role of the center of mass and the angles involved in tipping over.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant seeks assistance in determining the potential energy needed to tip a cherry picker and the angle required for tipping, emphasizing the simplification of the problem.
  • Another participant argues that tipping does not require energy input; instead, it releases energy when the center of mass moves outside the base of support.
  • A participant expresses gratitude for the response received, indicating engagement with the discussion.
  • A reference to another thread is provided, suggesting further reading on related topics.

Areas of Agreement / Disagreement

There is disagreement regarding the energy dynamics involved in tipping a cherry picker, with one participant asserting that tipping releases energy, while another is focused on calculating potential energy requirements.

Contextual Notes

The discussion does not resolve the assumptions regarding energy dynamics or the specific calculations needed for the tipping angle and potential energy.

Who May Find This Useful

Individuals interested in mechanical engineering, offshore operations, or the dynamics of mobile equipment in marine environments may find this discussion relevant.

glocki35
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Hi,

I have been tasked with working out load charts for various MEWPS (or cherry pickers) on board semi-submersible rigs, the iddea is to de-rate these in various sea states the same as an offshore crane, i have tried to simplify this as much as i can, however i am stuck when i try to work out the potential energy required to tip a cherry picker when the rig rolls and pitches (this is not a comprehensive engineering investigation, merely a simplification of what is required), i also would like to work out the inclination or angle required to make the cherry picker tip over.

Can anyone help with this?, i have attached a doc with sketches and figures to try and show you my way of thinking...

Thanks in advance

Glocki 35
 

Attachments

Engineering news on Phys.org
It doesn't take any energy to tip - it gives off energy that's why it happens.
You just need the CoG (technicaly the centre of mass) to move outside the base (ie the wheels) all pitching and rolling of a ship does is to provide the tip
 
Hi MGB_phys,

just wanted to say thanks for the reply, much appreciated :)
 

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