Find Center of Circle Inscribed in Parabola

In summary, to find the coordinate of the center of a circle inscribed in a parabola with the equation y=x^2, you can let the equation of the circle be x^2 + (y-c)^2 = 1, where c is the y-coordinate of the circle. By substituting y=x^2 into that equation and using the formula b^2 - 4ac = 0, you can find the value of c, which is 5/4. However, the resulting equation is quartic, which means there are actually two intersection points between the circle and the parabola. This is because when solving for x, you must take the square root of both sides, resulting in two values
  • #1
lkh1986
99
0
A circle with the radius of 1 unit is inscribed in a parabola with the equation of y=x^2. Find the coordinate of the center of the circle.

The answer given in the book is (0, 5/4).

I attempt this question by letting the equation of the circle be x^2 + (y-c)^2 = 1, where c is the y-coordinate of the circle. Then, by substitutuing y=x^2 into that equation, I obtain another equation. From the new equation, I try to use the formula b^2 - 4ac = 0. Then, I got the value of c, which is 5/4.

However, what I do not understand is this: The equation b^2 - 4ac = 0 means that 2 function intercept at only 1 point. But in this case, the circle touches the parabola at 2 points.

Do I get the answer c=5/4 by chance? Or is there any other method to solve this problem? Maybe the circle does not intercept the parabola at only 2 points? (I say this because I find that at the points of interception, it seems that the circle and the parabola do not share a same tangent line).
 
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  • #2
The resulting equation (when you substitute) is quartic: x^4+(1-2c)x^2+c^2=1
The reason you have two intersection points is because the solution to the quadratic formula in this case is actually x^2

x^2 = (-b +- sqrt(b^2-4ac))/(2a)

Even though the discriminant, being zero, causes the square root to drop out of the quadratic forumla (giving just one value on the right) you still have to take the square root of both sides to solve for x here, which gives two values of x in this case.

-GeoMike-
 
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  • #3


I would first clarify the question and make sure there are no typos or missing information. In this case, I would ask for clarification on the term "inscribed" as it can have different meanings in geometry. Does the circle intersect with the parabola at only two points or does it touch it at two points? This information is crucial in finding the center of the circle.

Assuming that the circle intersects with the parabola at only two points, the method you used to solve the problem is correct. However, it is possible that the given answer is incorrect and the correct answer could be (0, -5/4) as the circle could be inscribed in the parabola from the bottom.

To confirm the correct answer, I would suggest plotting the parabola and the circle on a graph and visually inspecting the points of intersection. Additionally, using calculus, you can find the derivative of the parabola and the circle at the points of intersection and see if they have the same slope, indicating that they share a tangent line.

In conclusion, as a scientist, I would approach this problem by clarifying any ambiguities in the question and using various methods to confirm the correct answer.
 

1. What is the definition of a circle inscribed in a parabola?

A circle inscribed in a parabola is a circle that touches the parabola at exactly one point and lies entirely within the parabola's curve.

2. How do you find the center of a circle inscribed in a parabola?

The center of a circle inscribed in a parabola can be found by finding the intersection point of the parabola's axis of symmetry and the perpendicular bisector of the chord that connects the points of tangency between the circle and the parabola.

3. Can a parabola have multiple circles inscribed within it?

Yes, a parabola can have multiple circles inscribed within it as long as the circles are tangent to the parabola at different points and do not overlap each other.

4. Is the center of a circle inscribed in a parabola always located on the parabola's axis of symmetry?

Yes, the center of a circle inscribed in a parabola is always located on the parabola's axis of symmetry. This is because the axis of symmetry is the perpendicular bisector of the chord connecting the points of tangency between the circle and the parabola, and the center must lie on this line in order for the circle to be tangent to the parabola at only one point.

5. Can the center of a circle inscribed in a parabola be found algebraically?

Yes, the center of a circle inscribed in a parabola can be found using algebraic equations and the properties of a parabola. This involves finding the vertex of the parabola, determining the equation of the axis of symmetry, and using the distance formula to find the distance between the vertex and the center of the circle inscribed in the parabola.

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