Circuit Analysis: Understand V2 & 3amp Equation

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SUMMARY

The discussion focuses on understanding the circuit analysis involving the voltage V2 and current of 3 amps. The user seeks clarification on how V2 equals 6 volts and the derivation of the linear equation that results in 3 amps. Key insights reveal that using Kirchhoff's Current Law (KCL) allows for the calculation of current through components, specifically noting that the total current at the junction is the sum of the currents through the 2Ω and 1Ω resistors, confirming that 1 + 2 equals 3 amps.

PREREQUISITES
  • Understanding of Kirchhoff's Current Law (KCL)
  • Basic knowledge of circuit components, specifically resistors
  • Familiarity with linear equations in electrical circuits
  • Ability to analyze simple electrical circuits
NEXT STEPS
  • Study Kirchhoff's Current Law (KCL) applications in circuit analysis
  • Learn how to derive linear equations from circuit components
  • Explore the relationship between voltage, current, and resistance using Ohm's Law
  • Practice solving circuit problems involving multiple resistors
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Students and professionals in electrical engineering, circuit designers, and anyone looking to enhance their understanding of circuit analysis and current calculations.

fran1942
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Hello, I have tried really hard to understand this circuit but I just can't grasp it.

I am trying to understand how V2 comes to 6 volts ie. where does the 3amp come from that is multiplied by the value of V2 to give 6 volts.
It would help a lot if I could see the linear equation which gives 3 amps for the relevant loop.

Thanks kindly for any help with this.
 

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hello fran1942! :smile:

use KCL to find the current through the bottom wire, directly under the 2Ω …

how much is that, and how does it help you to find the current through the 2Ω itself? :wink:
 
OK thanks. I see that current will be the combination of the 2 and the 1, making 3. Is it as simple as that ?

The main thing bugging me was that I could not work out the linear equation to give that 3amps.
Could someone please help with that equation.

Thanks again.
 
fran1942 said:
… I could not work out the linear equation to give that 3amps.

not following you …

the KCL linear equation for that junction under I2 is 1 + 2 = 3 …

what is worrying you about that? :confused:​
 

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