All variables are given by the circuit unless otherwise stated
a) Derive an expression for the ratio (Vo/Vs)
KCL and KVL equations
The Attempt at a Solution
-Vs+ .05Vo +(2.5kΩ/2.55kΩ)Vp = 0 where,
Vs = .05Vo + (2.5kΩ/2.55kΩ)Vp for the left circuit.
Then for the right circuit:
Rs2= 3.70kΩ where
i= .08Vp/3.70kΩ, so
Vo = iR
=(.08Vp/3.7kΩ)*20kΩ, solving for Vp gives me
Vp= Vo/.432 I then substituted this into my Vs equation and solved for (Vo/Vs) and was given a ratio of .432.
Now im not sure if my approach to this problem is right but i think the logic in going this way seems right to me. Any help or criticism would be greatly appreciated.