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Circuit Analysis using KVL and KCL

  1. Feb 11, 2013 #1
    1. The problem statement, all variables and given/known data
    Circuit_zps7dbcb83c.png

    All variables are given by the circuit unless otherwise stated

    a) Derive an expression for the ratio (Vo/Vs)

    2. Relevant equations
    KCL and KVL equations


    3. The attempt at a solution

    Rs1=2.55kΩ
    -Vs+ .05Vo +(2.5kΩ/2.55kΩ)Vp = 0 where,

    Vs = .05Vo + (2.5kΩ/2.55kΩ)Vp for the left circuit.

    Then for the right circuit:

    Rs2= 3.70kΩ where

    .08Vp=iRs

    i= .08Vp/3.70kΩ, so

    Vo = iR
    =(.08Vp/3.7kΩ)*20kΩ, solving for Vp gives me

    Vp= Vo/.432 I then substituted this into my Vs equation and solved for (Vo/Vs) and was given a ratio of .432.

    Now im not sure if my approach to this problem is right but i think the logic in going this way seems right to me. Any help or criticism would be greatly appreciated.
     
  2. jcsd
  3. Feb 11, 2013 #2

    gneill

    User Avatar

    Staff: Mentor

    The 0.08Vp source is a current source. So Vo = -0.08Vp*Rs2 ....(note the direction of current flow implied by the source).
     
  4. Feb 11, 2013 #3
    Yea I realized that its actually a current source and was able to solve the problem, my initial approach was totally off.
     
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