Circuit Calculation - Mesh Analysis

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SUMMARY

The discussion focuses on solving circuit calculations using mesh analysis to determine the current I(t) and voltage V2(t) in a circuit with impedances. The user initially converts circuit elements to their respective impedances (zc1, zr1, zc2, zr2, zc3) and applies mesh analysis. An expert confirms that while the approach is valid for a fixed frequency sinusoidal source, it is unnecessary to consider capacitor C1 due to its position across the voltage supply, allowing for simplification through voltage divider techniques.

PREREQUISITES
  • Understanding of mesh analysis in electrical circuits
  • Knowledge of impedance in AC circuits
  • Familiarity with voltage dividers
  • Basic concepts of sinusoidal sources in circuit analysis
NEXT STEPS
  • Study mesh analysis techniques in detail
  • Learn about calculating impedances for capacitors and resistors in AC circuits
  • Explore voltage divider rules and their applications in circuit simplification
  • Investigate the effects of ideal voltage sources on circuit behavior
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing AC circuits using mesh analysis techniques.

brighton53
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Homework Statement


Hi, I'm trying to find what I(t) and V2(t).
https://dl.dropbox.com/u/672601023

The Attempt at a Solution


- Firstly I'm changing to impedances and then predefining a few new variables
- zc1, zr1, zc2, zr2 and zc3
- then I'm going to do mesh analysis
https://dl.dropbox.com/u/67260102/as.png

and then the current I'm trying to work out should be the answer of I2.

and the voltage I'm trying to also workout will do Zc3 * I3.

Is all of this correct?
 
Last edited by a moderator:
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Hi brighton53, Welcome to Physics Forums.

Sure, you can solve the problem that way if V is a fixed frequency sinusoidal source. It's a bit of overkill, but will get the job done.

Note that C1 is directly across the voltage supply, and that ideal voltage supplies are immune to loading. So if you're looking for I(t) and V2(t) you can ignore C1 entirely. Then you could combine R1 with C2, and R2 with C3 into two net impedances and solve as a voltage divider...
 

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