Find Vx. With R1, R2 and i3 given.
*In my attachment, I renamed the given values.*
KCL, KVL, Ohm's law
The Attempt at a Solution
For KVL, I solved for V3 in L2 then subbed it in L1 to give:
3Vx - Vx + V1 = 0
From here, I tried to get my KCL equations to have i1 in terms of i3 so I could replace V1 with R1 and i1. But the KCL won't let me do that.. in fact, I can't get any of those KCL equations in different terms they just cancel each other out in every case.
I'm lost if this is an error in the problem or I'm doing something wrong. Thanks for any help.
16.2 KB Views: 332