[Circuits] Calculating the power absorbed by a resistor

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ainster31
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Homework Statement



yAw0XtS.png


Homework Equations





The Attempt at a Solution



Attached to this post.

I have calculated the power absorbed for the 6S and 5S resistors but not the 3S resistor.
 

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ainster31 said:

Homework Statement



yAw0XtS.png


Homework Equations





The Attempt at a Solution



Attached to this post.

I have calculated the power absorbed for the 6S and 5S resistors but not the 3S resistor.

Your values look okay for the 6S and 5S resistors. Why didn't you calculate the power absorbed by the 3S resistor?
 
gneill said:
Your values look okay for the 6S and 5S resistors. Why didn't you calculate the power absorbed by the 3S resistor?

Here is my attempt for the 3S resistor:

$$R=\frac { V }{ I } \\ \frac { 1 }{ 3 } =\frac { V }{ 6 } \\ V=2\quad V\\ \\ P=VI\\ P=2\cdot 16\\ P=32\quad W$$
 
ainster31 said:
Here is my attempt for the 3S resistor:

$$R=\frac { V }{ I } \\ \frac { 1 }{ 3 } =\frac { V }{ 6 } \\ V=2\quad V\\ \\ P=VI\\ P=2\cdot 16\\ P=32\quad W$$

Where did you get 16 A from for your P = VI calculation? You used I = 6 A in the second line.

Note that while power is indeed given by P = VI, for a resistor it's also given by V2/R and I2R, so you can avoid some steps if you already have either V or I.
 
Conclusion.

I used 16 A by accident. Not sure where I got the 1 from.