Circular motion: Car driving along a circular hill

AI Thread Summary
The discussion focuses on calculating the force exerted on a car traveling at constant speed along the top of a circular hill. The correct expression for the force from the hill is F = mg - (mv^2)/r, which accounts for the centripetal acceleration. At the top of the hill, the normal force is not simply equal to mg due to this acceleration. Newton's second law is applied to derive the relationship between the forces acting on the car. Understanding the role of centripetal acceleration is crucial for solving this problem accurately.
Acid92
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Homework Statement


A car of mass m is traveling along a circular hill of radius r with a constant speed v, write an expression for the force "on the car from the hill" when the car is at the top of the hill

Homework Equations


F (weight) = mg
F (centripetal) = mv^2 /r

The Attempt at a Solution


I think the force on the car from the hill is the normal to the car which at the top of the hill seems to me to be mg. The actual answer is F = mg - (mv^2)/r, I can't seem to figure out how theyve come to this.
 
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Acid92 said:
I think the force on the car from the hill is the normal to the car which at the top of the hill seems to me to be mg. The actual answer is F = mg - (mv^2)/r, I can't seem to figure out how theyve come to this.
The normal force at the top of the hill would equal mg if there were no acceleration. But there is acceleration, so apply Newton's 2nd law to figure out the normal force.
 
Doc Al said:
The normal force at the top of the hill would equal mg if there were no acceleration. But there is acceleration, so apply Newton's 2nd law to figure out the normal force.

Ah right, I forgot that there would be a centripetal acceleration even when the car is at the top of the hill, thanks!

mg - normal = ma = m(v^2 /r)
normal = mg =(mv^2)/r
 
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