Circular motion comparisons question

AI Thread Summary
When a bus of weight Fg moves over a hill and a dip with the same radius of curvature, the normal force at the hill's crest is 3/4 Fg. To find the normal force at the bottom of the dip, it is essential to understand the relationship between weight, normal force, and acceleration. The acceleration remains constant in both scenarios but acts in opposite directions. The solution indicates that the normal force at the dip's bottom is 5/4 Fg. Understanding these dynamics is crucial for solving circular motion problems.
jakeinater

Homework Statement


A bus of weight Fg is moving at a constant speed over a hill and then over a dip that has the same radius of curvature, when the bus passes over the crest of the hill, the road exerts a normal force on the bus equal to 3/4 Fg. What is the normal force the road exerts on the bus when it is passing through the bottom of the dip

Homework Equations


netF=ma a=v^2/r

The Attempt at a Solution


I have stared at this question for an hour and don't even know where to start, the answer is 5/4 Fg which seems simple but I don't know how they got that. First post so sorry for any formatting errors.[/B]
 
Physics news on Phys.org
Hint: The acceleration of the bus is the same in both cases, but in opposite directions, since the velocity and radius are the same. How does the weight, normal force, and acceleration relate to each other?
 
  • Like
Likes jakeinater
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanged mass'

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Question Regarding Circular Motion and Normal Forces
Replies
2
Views
3K
Acceleration in uniform circular motion is uniform or non-uniform?
2
Replies
55
Views
3K
[Grade 12 Physics] Circular/gravitational motion
Replies
21
Views
3K
Circular Motion of a Cyclist and a Car going around a bend in the road
Replies
6
Views
4K
Circular motion grade 12 physics
Replies
4
Views
2K
Circular Motion Questions (energies, forces, angular velocities, etc.)
Replies
2
Views
1K
Circular motion - ball in a loop
Replies
19
Views
4K
Circular motion under gravity; a car travelling on hills
Replies
2
Views
6K
Acceleration and Gravity with Circular Motion
Replies
9
Views
3K
Circular Motion -- Swinging keys on a string in a vertical circle
Replies
6
Views
4K

Hot Threads

Recent Insights

Back
Top