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Circular Motion-When Will They Meet?

  1. Oct 22, 2006 #1
    Here I am again...
    Two people start at the same place and walk around a circular lake in opposite directions. One has an angular speed of 1.66E-3 rad/s, while the other has an angular speed of 3.24E-3 rad/s. How long will it be before they meet?

    What I have done so far is to set 3.24t + 1.66t=2Pi

    so t(4.9)=2Pi therefor t=1.282 s

    or so I thought...problem is that it's wrong.
    So then what am I doing wrong?
    Any help is appreciated.
     
  2. jcsd
  3. Oct 22, 2006 #2

    radou

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    Btw, where did the 'E-3' parts dissapear?
     
  4. Oct 22, 2006 #3
    i thought that that was just notation
    what does it really mean?
     
  5. Oct 22, 2006 #4

    radou

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    1.66E-3 = [tex]1.66\cdot 10^{-3}[/tex]. It is usually written in text form as 1.66*10^-3, rather than 1.66E-3.
     
  6. Oct 22, 2006 #5
    i can't believe that was all I had to do
    been struggling for hours
    Thank you so much!
     
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