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Circus Clown Velocity question

  1. Mar 17, 2014 #1

    a.k

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    1. The problem statement, all variables and given/known data
    A 75-kg clown at the circus escapes from a tower by jumping from a platform located 35 m above a safety net held by six other clowns. If air resistance exerts a 110 N force on the clown as he falls, what is his velocity just before he hits the net?


    2. Relevant equations
    F=mg-air resistance
    a=f/m


    3. The attempt at a solution
    75kg-9.8 m/s^2-110N
    735-110
    F=625 N

    625/75
    a=8.33 m/s^2

    I am drawing a blank as to what velocity formula I can use in the problem.
     
  2. jcsd
  3. Mar 17, 2014 #2
    Try this one:
    $$v_{f}^{2} = v_{0}^{2} + 2a\Delta y$$
    Make sure to watch your signs on ##a## and ##\Delta y## though.
     
  4. Mar 17, 2014 #3

    a.k

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    2(8.33)35m
    16.66*35
    =583.1 m/s^2
     
  5. Mar 17, 2014 #4

    That's really fast, I think you forgot to take the square root :)

    Also your units are for acceleration, not velocity.
     
  6. Mar 17, 2014 #5
    Hey there!
    Just wanted to point this out in case you have that picky teacher or professor who devotes their life to signs - in regards to your acceleration, do keep in mind which way the clown is accelerating(you're saying he accelerates upwards with your value).

    Other than that, Post #4 is your way to solving this one.
     
  7. Mar 18, 2014 #6

    a.k

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    Thanks for the help.
     
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