Classical radius of an electron and its implications prob.

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Homework Help Overview

The problem involves calculating the time required for an electron to gain energy using classical physics concepts, specifically in the context of the classical radius of an electron and the intensity of sunlight. It also prompts a comparison with the photoelectric effect.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between power, intensity, and energy to determine the time required for the electron to gain energy. There are attempts to derive equations involving the area of the electron and the power incident on it.

Discussion Status

The discussion includes various approaches to relate power and time, with some participants providing insights into using the area of the electron and the formula for power. There is acknowledgment of the difference in electron emission times between classical and modern physics, but no consensus has been reached on a specific method or solution.

Contextual Notes

Participants note the challenge of finding the appropriate equations and the differences in time scales for electron emission in classical versus modern physics contexts.

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Homework Statement


The classical radius of an electron is 2.82 x 10-15 m. If a material is radiated with sunlight with an intensity of 500W/m2, calculate using classical arguments the time required for an electron to gain an energy of 1eV. How does this result compare with electron emission in the photo-electric effect?


Homework Equations


[tex]E= hf[/tex]


The Attempt at a Solution



I completely do not have any idea how to do this question. Can anyone provide my with the necessary equation. So far i do not have any idea which equation has " t" in it.

And the difference between classical and modern physics is :
Electrons are emitted from the surface almost instantaneously (less than 10-9 secs) even at low intensities.
Classically the electrons would require some time to absorb the incident radiation before they acquire enough kinetic energy to escape from the metal.

Any help will be greatly appreciated.
 
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Since we are given a power in the intensity, once you find the energy required in terms of the power, you can find the time.
 
Not too sure about this, but since you know the radius of the electron, you can get its area, A.

You can then get the power emitted onto the electron.

P=IA

Now P=Et, solve for t. Don't forget to use the same units here.

As for comparing, find some way to get wavelength, i guess, from the intensity you are given and use E=hf.
 
kk got it thanks.
 

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