Clausius-Clapeyron Equation, and Cubic Unit Cells

AI Thread Summary
The discussion revolves around applying the Clausius-Clapeyron equation to determine the boiling point of acetone at 580 mmHg and calculating the atomic radius of chromium in a body-centered cubic structure. The first participant expresses confusion about the calculations and seeks clarification on the equation involving pressure and temperature changes. For the second question, they outline the steps to find the mass of a unit cell and the necessary conversions to determine the atomic radius, but are unsure about the arithmetic involved. Another participant reassures them that they understand the concepts and emphasizes that the remaining steps are primarily arithmetic. The conversation highlights the challenges of applying theoretical concepts to practical problems in chemistry.
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1. Acetone has normal boiling point of 56.5 oC, and heat of vaporization of 32.0 kJ/mol. Find the boiling point at 580 mmHg.


2. Given element, its structure and density, find its atomic radius in pm. Cr, body centered cubic, 7.19 g/mL.


Well, as for question 1, I'm totally stumped. Everytime I try to go about doing any problem like this, my brain locks up. I think I just don't have a firm understanding of the idea.

Number 2, well, umm...again, same as above. I really just don't understand anything. It's pretty frustrating. So if someone could help me pleaseeeee, I will become their slave.
 
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I've thought about the first question a bit more.

Is \frac{lnP_2 - lnP_1}{\frac{1}{T_2} - \frac {1}{T_1}} = - \frac{\Delta H}{R} what I'm looking for?
 
I'm not crazy, talking to myself am I?

Anyways, regarding the second question.

First I have to determine the mass of a single unit cell.

I believe, this is found by determining the molar mass of Cr, then converting it to amu's. Since there are 2 nuclei in a body centered cubic cell, it would be 2x Molar Mass(in amu) correct?

Now, in order to determine the actual radius, I need to use density fomrula. V_{unit cell} = \frac {m_{unit cell}}{d}

But first I convert mL into cubic whats? I forget...oh well. Anyways, from there, I convert to picometers, then I take the cube of this number, which is "s". But I can't use this yet. Sooooo, I use \frac {\sqrt{3}s}{4} = r.


Someone please verify these?
 
Is no one going to reply to this? Or should I post these in chemistry forum?
 
You're doing fine --- you got the concepts --- at that point, it becomes an exercise in arithmetic.
 
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