Closed Universe - FRW Equation

In summary, the FRW equations can be satisfied by showing that the metric when ##\eta## is taken as time is equal to the LHS of the FRW equation with a spatial curvature term added. This can be achieved by relating ##\eta## to ##\eta_0## and using the values for ##\rho## and ##H_0##.
  • #1
unscientific
1,734
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Homework Statement



(a) Show that the equations satisfy FRW equations.
(b) Show the metric when ##\eta## is taken as time

frw1.png

Homework Equations

The Attempt at a Solution



[/B]
The FRW equation is:
[tex] 3 \left( \frac{\dot a}{a} \right)^2 = 8\pi G \rho [/tex]

Using ##\frac{da}{dt} = \frac{da}{d\eta} \frac{d\eta}{dt}##:

[tex] \dot a = \frac{\frac{1}{\eta_*} sin \left( \frac{\eta}{\eta_*}\right)}{1 - cos \left( \frac{\eta}{\eta_*} \right)} [/tex]
[tex]\dot a = \frac{C sin \left( \frac{\eta}{\eta_*} \right)}{\eta_* a} [/tex]

The LHS is then

[tex] 3 \left( \frac{\dot a}{a} \right)^2 = 3 \left[ \frac{C^2 sin^2 (\frac{\eta}{\eta_*})}{\eta_*^2 a^4} \right] [/tex]Not sure how to show this equals RHS..
 
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  • #2
unscientific said:

Homework Statement



(a) Show that the equations satisfy FRW equations.
(b) Show the metric when ##\eta## is taken as time

frw1.png

Homework Equations

The Attempt at a Solution



[/B]
The FRW equation is:
[tex] 3 \left( \frac{\dot a}{a} \right)^2 = 8\pi G \rho [/tex]

Using ##\frac{da}{dt} = \frac{da}{d\eta} \frac{d\eta}{dt}##:

[tex] \dot a = \frac{\frac{1}{\eta_*} sin \left( \frac{\eta}{\eta_*}\right)}{1 - cos \left( \frac{\eta}{\eta_*} \right)} [/tex]
[tex]\dot a = \frac{C sin \left( \frac{\eta}{\eta_*} \right)}{\eta_* a} [/tex]

The LHS is then

[tex] 3 \left( \frac{\dot a}{a} \right)^2 = 3 \left[ \frac{C^2 sin^2 (\frac{\eta}{\eta_*})}{\eta_*^2 a^4} \right] [/tex]Not sure how to show this equals RHS..

In a closed universe the FRW equation has a spatial curvature term with a 'k' in it. You omitted that.
 
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  • #3
Dick said:
In a closed universe the FRW equation has a spatial curvature term with a 'k' in it. You omitted that.

FRW equation is given by:
[tex]3 \left( \frac{\dot a}{a} \right)^2 + \frac{kc^2}{a^2} = 8\pi G \rho [/tex]

Curvature parameter is given by ##\Omega = \frac{8\pi \rho G}{3H_0^2}##.

[tex] \frac{C^2 sin^2 (\frac{\eta}{\eta_*})}{\eta_*^2 a^4} + \frac{kc^2}{a^2} = \frac{\Omega}{H_0^2} [/tex]

At ##t=0##, ##\frac{\eta_0}{\eta_*} = sin (\frac{\eta_0}{\eta_*})##, so ##a_0 = C\left[ 1 - \sqrt{1 - (\frac{\eta_0}{\eta_*})^2} \right]##.

Rearranging, ##(\frac{\eta_0}{\eta_*})^2 = (\frac{a_0}{c})(1 - \frac{a_0}{c})##.

How am I to relate ##\eta## to ##\eta_0##?
 
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  • #4
I'm just confused at this stage, shouldn't ##a_0 =1##? I have a feeling this problem is much simpler than it seems..Would appreciate some help
 
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  • #5
5th Attempt

[tex] \left( \frac{\dot a}{a}\right)^2 = \frac{8\pi G \rho}{3} - \frac{kc^2}{a^2} [/tex]

Using ##\rho = \Omega \rho_c = \Omega \cdot \frac{3H^2}{8\pi G}##:

[tex] \left( \frac{\dot a}{a}\right)^2 = \Omega H^2 - \frac{kc^2}{a^2} [/tex]

[tex] \dot {a}^2 = \Omega \dot {a}^2 - kc^2 [/tex]

[tex] \frac{da}{dt} = c \sqrt{\frac{k}{\Omega -1}} [/tex]

But there is no factor of ##C## on the LHS, as ##\frac{da}{dt} = \frac{sin(\frac{\eta}{\eta_*})}{\eta_* \left[1-cos(\frac{\eta}{\eta_*})\right]}##
 

1. What is a closed universe in the context of the FRW equation?

A closed universe is a theoretical model used in cosmology that describes the entire universe as a finite, closed, and bound system. This means that the universe has a finite amount of matter and energy, and is not infinitely expanding like an open universe.

2. How is the FRW equation used to describe a closed universe?

The Friedmann-Robertson-Walker (FRW) equation is a set of mathematical equations that describe the evolution of the universe, including its density, expansion rate, and curvature. In the case of a closed universe, the FRW equation takes into account the positive spatial curvature of space, which results in a universe that eventually collapses in on itself.

3. What are the implications of a closed universe according to the FRW equation?

If the universe is indeed closed, it means that it has a finite lifespan and will eventually collapse in on itself due to the gravitational pull of its own mass. This would result in a catastrophic event known as the "Big Crunch", where all matter and energy in the universe would be compressed into an infinitely small point.

4. How do we know if the universe is closed or open?

Currently, the evidence suggests that the universe is flat, which means it has a balance between positive and negative spatial curvature. However, the exact geometry of the universe is still an open question in cosmology, and more data and research is needed to determine if the universe is closed or open.

5. What implications does a closed universe have for the fate of the universe?

If the universe is closed, it means that it has a finite lifespan and will eventually collapse. This has significant implications for the ultimate fate of the universe, as it would mean that the expansion of the universe will eventually stop, and the universe will begin to contract. This could potentially lead to a cyclic model of the universe, where the universe expands and contracts in an endless cycle.

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