CMOS Regions of Operation Problem

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tsaitea
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In the attached photo, I found M2 to be triode region b/c the drain and drain source voltage is 0 which will always be less than the output voltage.

However, I am have troubles finding M1's region of operation, VDS >= VGS - VTH.
Vout - Vbias >= Vdd - Vbias - VTH **Vbias = 0.8 V , VTH = 0.5 V.

Vout >= Vdd - VTH

Im at this point now b/c Vout may vary.
 

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CWatters said:
For the moment assume Vin(t) = 0.

For the Fet to be on the gate voltage must be more than Vth below the source. In other words Vbias > Vdd+Vth.

So assuming Vin = 0, for the FET to be on VGS > VTH.

Where VG = VDD and VS = Vbias therefore,

VDD - Vbias > VTH

Vbias < VDD-VTH

I don't quite see where you got Vbias > Vdd + Vth from :confused:
 
rude man said:
You have not stated your problem.

M2 has no effect whatsoever on the output voltage unless the gate breakdown voltages are exceeded.

Right so for M2 Vout > Vth ,

For triode,

VDS2 < VGS2 - Vth
0 < Vout - Vth and since Vout > Vth,
M2 will be in triode.
 
tsaitea said:
So assuming Vin = 0, for the FET to be on VGS > VTH.

Where VG = VDD and VS = Vbias therefore,

VDD - Vbias > VTH

Vbias < VDD-VTH

I don't quite see where you got Vbias > Vdd + Vth from :confused:

M1 is a P type FET. So if I remember correctly the gate (VDD) has to be below the drain/source for it to be ON. Therefore Vbias must be > Gate + Vth.

M2 appears to be configured as a capacitor.
 
CWatters said:
M1 is a P type FET.

I don't think so. It's an N type.

The more conventional symbol for an N type is an arrow pointing into the substrate, but the alternative symbol is the source pointing away from the device, with no subtrate indicated.
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