Find output current of NMOS transistor

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SUMMARY

The discussion focuses on calculating the output current of NMOS transistors in different operating regions. For NMOS1, operating in the saturation region with a gate-source voltage (Vgs) of 1.5V, the drain current (Ids) is calculated to be 1.08mA using the equation Id = Kn * (Vgs-Vt)^2/2. For NMOS2, operating in the triode region with a gate-source voltage of 4.5V, the drain current is determined to be 7.248mA using the equation Id = Kn * ((Vgs-Vt)Vds - Vds^2/2). The calculations utilize parameters such as threshold voltage (Vtn), width-to-length ratio (W/L), and mobility (un).

PREREQUISITES
  • Understanding of NMOS transistor operation and regions (saturation and triode).
  • Familiarity with the equations for drain current (Ids) in both saturation and triode regions.
  • Knowledge of key parameters: threshold voltage (Vtn), mobility (un), and width-to-length ratio (W/L).
  • Basic understanding of semiconductor physics and device characteristics.
NEXT STEPS
  • Study the impact of varying the width-to-length ratio (W/L) on NMOS performance.
  • Learn about the effects of temperature on NMOS transistor characteristics.
  • Explore advanced modeling techniques for NMOS transistors using SPICE simulations.
  • Investigate the design considerations for NMOS transistors in integrated circuits.
USEFUL FOR

Electrical engineers, students studying semiconductor devices, and professionals involved in circuit design and analysis will benefit from this discussion.

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Homework Statement


Vtn = 0.4V
W/L = 10
NMOS1
Saturation Region
Drain = 2.5V
Gate = 1.9V
Source = 0V

Vtn = 0.4V
W/L = 10
NMOS2
Triode/Linear/Ohmic Region
Drain = 0.5V
Gate = 2.2V
Source = -2.3V

tox = 9um
un = 250cm^2/V
W/L = 10

Homework Equations


Saturation: Id = Kn * (Vgs-Vt)^2/2
Triode/Linear/Ohmic: Id = Kn * ((Vgs-Vt)Vds - Vds^2/2)

The Attempt at a Solution


tox = 9nm
un = 250cm^2/V
cox = eox/tox = (3.9*8.85*10^-14F/cm)/9nm = 0.003835F/m^2
kn = un*cox*W/L = 95.875uA/V^2

NMOS1
Ids = Kn * (Vgs-Vt)^2/2 = 1.08mA

NMOS2
Vds = Vd - Vs = 0.5-(-2.3)=2.8V
Ids = Kn * (Vgs-Vt)(Vds) - Vds^2/2) = 7.248mA
 
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