Coefficient of Friction of a olympic skier

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SUMMARY

The discussion focuses on calculating the coefficient of friction (Mk) for an Olympic skier moving down a 30-degree slope at 20.0 m/s, who slides 145 m on wet snow before stopping. Participants emphasize the importance of using kinematics to determine deceleration and the need to analyze forces using free body diagrams. The key takeaway is that mass is not required to find the coefficient of friction, as it cancels out in the equations. The correct approach involves applying Newton's second law and breaking forces into their x and y components.

PREREQUISITES
  • Understanding of kinematics equations, specifically Vf^2 = Vo^2 + 2ad
  • Familiarity with Newton's second law of motion
  • Ability to draw and analyze free body diagrams
  • Knowledge of potential energy (PE) and kinetic energy (KE) concepts
NEXT STEPS
  • Study the application of Newton's second law in inclined plane problems
  • Learn how to break forces into x and y components for analysis
  • Explore the relationship between deceleration and frictional force
  • Practice solving similar physics problems involving coefficients of friction
USEFUL FOR

Students in introductory physics courses, educators teaching mechanics, and anyone interested in understanding the dynamics of motion on inclined surfaces.

William Bush
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1. The problem statement
An olympic skier moving at 20.0 m/s down a 30.0 degree slope encounters a region of wet snow and slides 145 m before coming to a halt. What is the coefficient of friction between the skis and the snow?




2. Homework Equations
Mk=Ff/Fn
FdCosO=1/2MVf^2-1/2MVo^2




3. The Attempt at a Solution
Drew free body diagram and identified the forces acting on the skier to be the normal force (Fn), gravity (mg), and Ff (frictional force). Fn and mg cancel each other out so the only other force to consider is Ff. I figured I could use the work/kinetic energy formula to find Ff then plug the answer into the formula for Mk. Problem is that I need the mass of the skier for my plan to work.
 
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think of the equation that does not require mass. (or it might cancel out!)
 
The only equation I can think of where mass will cancel out is: PE (potential energy) at the top equals KE (kinetic energy at the bottom). I don't think this is the equation you are referring to is it?
 
think of it this way. The skier skied down with velocity 20 m/s and 30 degrees downwards stopped (or is in rest) in distance 145 meters.
would the mass of the skier be really necessary?
 
It's obvious that I missing a key concept. With info given in the problem, I can find acceleration, the height of the slope and even the time it took to travel 145 meters. But I'm not seeing a way to find the frictional force. I am 3 months into my very first physics class so it's possible that there is another formula or concept that I am not remembering.
 
hmm

i kept thinking that this problem was to find time!
I believe u need the mass to find the friction force.
 
No you don't need the mass, since you will know the deceleration caused by the friction force. And as acceleration is Force per mass, the mass will cancel out each other when you make your calculation later.
 
I'm still not following...how do I determine deceleration?
 
William Bush said:
I'm still not following...how do I determine deceleration?

You can just use kinematics to get the deceleration, using the information about the velocity and distance stated in the question.

After that, draw a free body diagram and sum up the forces in each direction. That will give you everything you need to solve for the coefficient of friction.
 
Last edited:
  • #10
1. Is deceleration the same as acceleration but just in the opposite direction?

2. When I use the kinematics equation Vf^2=Vo^2+2ad, I get 1.38m/s for acceleration/deceleration. If I'm right so far, how do I use that info?

3. After drawing the free body diagram, I have three forces; Fn, Ff, and mg. Fn and Ff cancel each other out so the only one I have to be concerned with is Ff. I don't know how to use the value I obtained for deceleration to help me find Ff.
 
  • #11
1. Yes. The word deceleration is sometimes used to indicate that an object is slowing down (rate of change of velocity is decreasing).

2. That's right, but watch your signs. You're going to be using Newton's second law, so that's why you need to know acceleration.

3. I don't understand this:

I have three forces; Fn, Ff, and mg. Fn and Ff cancel each other out so the only one I have to be concerned with is Ff.

Fn and Ff cancel, but you're left with Fn?? What I think you meant to say (correct me if I'm wrong) is that Fn and mg cancel. Well, remember, the skier is on an incline. Have you learned how to break up forces into x and y components? That is what you need to do here. You will use Newton's second law to get two equations. One in the x direction, and one in the y direction.
 

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