Coefficient Of Kinetic Friction

AI Thread Summary
To determine the coefficient of kinetic friction between a hockey puck and ice, the puck is given an initial speed of 20.0 m/s and slides for 115 minutes before stopping. The equations of motion and energy are applied, including v = u + at and v^2 - u^2 = 2aS, to calculate acceleration and distance. The kinetic energy equation (1/2)mv^2 = μmgS is used to relate the coefficient of friction to the distance traveled. Despite attempts to solve using these formulas, the correct coefficient of kinetic friction remains elusive. The discussion emphasizes the need for accurate calculations to derive the desired friction coefficient.
Joshw17_15
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A hockey puck on a frozen pond is given an initial speed of 20.0 m/s. If the puck always
remains on the ice and slides 115 min before coming to rest, determine the coefficient of
kinetic friction between the puck and ice.




[v = u + a*t
=> 0 = 20 - a* 115*60
=> a = 20/(115*60)

v^2 - u^2 = 2*a*S
=> S = 400*(115*60)/2*20



(1/2)*m*v^2 = u*m*g*S
=> u = (1/2)*v^2/S*g
=> u = (1/2) * 400/S*9.8

I use these equations and I can't seem to come up with right answer
 
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Joshw17_15 said:
(1/2)*m*v^2 = u*m*g*S
=> u = (1/2)*v^2/S*g
=> u = (1/2) * 400/S*9.8

I use these equations and I can't seem to come up with right answer

This should give the correct answer.

1/2mv2=μmg(115)
 
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