Coefficient of restitution and velocity

AI Thread Summary
The coefficient of restitution defines the ratio of the velocity of separation to the velocity of approach during a head-on collision. A coefficient greater than one suggests that the velocity of separation exceeds that of approach, indicating a superelastic collision where kinetic energy increases post-collision. This scenario implies that mechanical energy is not conserved, as some internal energy has been converted to kinetic energy. In contrast, a perfectly inelastic collision results in a separation velocity of zero. The discussion highlights the nuances of collision types and their implications for energy conservation.
Parikshit M
Messages
4
Reaction score
0
We know that the ratio of velocity of separation to the velocity of approach of two bodies in a head on collision is called coefficient of restitution .Is there no possibility that the velocity of separation is quite larger than that of approach? or vice versa? can't the ratio be more than 1 or less than 0 ?
 
Physics news on Phys.org
Parikshit M said:
Is there no possibility that the velocity of separation is quite larger than that of approach? or vice versa?
Those are two very different situations. For example, if the bodies stick together (a perfectly inelastic collision) the separation velocity will be zero.

What do you think a coefficient of restitution greater than one would imply?
 
Doc Al said:
Those are two very different situations. For example, if the bodies stick together (a perfectly inelastic collision) the separation velocity will be zero.

What do you think a coefficient of restitution greater than one would imply?
It would imply that the velocity of separation is greater than that of approach .
 
And what of the energy?
 
Parikshit M said:
It would imply that the velocity of separation is greater than that of approach .
Well, yes. But what does that imply as far as energy goes?
 
energy increases?.. due to increase in velocity , kinetic energy increases and hence final kinetic energy will be greater.So does that mean mechanical energy is not conserved?
 
Parikshit M said:
So does that mean mechanical energy is not conserved?
That's correct. A collision where the kinetic energy is greater after the collision than before would be an example of a superelastic collision--mechanical energy is not conserved. Some internal energy of the system must have been converted to mechanical kinetic energy. Not the typical collision between two objects.
 
  • Like
Likes Parikshit M
thanks a lot my books never said anything about super elastic collisions , delighted ! thanks again
 
Back
Top