B Coefficient of Restitution in x and y

AI Thread Summary
To calculate the direction of objects after a two-body collision, it is valid to break down the relative velocities into x and y components, especially in a two-dimensional plane. For linear collisions, one can assign positive and negative velocities based on a fixed orientation of the line. When analyzing collisions involving angles, such as 120 degrees, the velocities can be expressed in terms of their components, with the coefficient of restitution (denoted as e_x) applied accordingly. It is essential to assign appropriate signs to each component to accurately describe the collision dynamics. Understanding these principles aids in effectively analyzing and predicting the outcomes of collisions.
unseeingdog
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I am currently studying collisions in high school and my teacher told us that, in order to calculate the direction of each object after a 2-body collision, we could change the values in the relative velocity terms of the equation of the coefficient of restitution to the components in x and y. Is this true? Thanks.
 
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If collisions are on a line, you can fix a positive orientation of the line so you have positive and negative velocities respect the two opposit directions... it is possible to interpret the minus in front of the vector as a velocity in the opposite sense ...
If the collision is in the plane you can always do the same component by component ...
I don't know if I answered ...
Ssnow
 
Ssnow said:
If collisions are on a line, you can fix a positive orientation of the line so you have positive and negative velocities respect the two opposit directions... it is possible to interpret the minus in front of the vector as a velocity in the opposite sense ...
If the collision is in the plane you can always do the same component by component ...
I don't know if I answered ...
Ssnow
So, say, if one of the bodies moves along the x axis, and the other moves with an angle of 120 with respect to the horizontal, one can write ##e_x = (v_2cos(120) - v_1)/(u_1 - u_2cos(120)## ?
 
mmmmh, what is ##e_{x}## ? ... if the ##\vec{v}=(v_{1},v_{2})## is the first vector and ##\vec{u}=(u_{1},u_{2})## the second forming an angle of ##120°## then ##\vec{v}=(v_{1},0)## because is on the ##x## axis and ##\vec{u}=(u\cos{(120)},u\sin{(120)})## where ##u## is the magnitude of ##\vec{u}##. Now you must fix a sign ##\pm## to each component that describes the collision ...
Ssnow
 
Ssnow said:
mmmmh, what is ##e_{x}## ? ... if the ##\vec{v}=(v_{1},v_{2})## is the first vector and ##\vec{u}=(u_{1},u_{2})## the second forming an angle of ##120°## then ##\vec{v}=(v_{1},0)## because is on the ##x## axis and ##\vec{u}=(u\cos{(120)},u\sin{(120)})## where ##u## is the magnitude of ##\vec{u}##. Now you must fix a sign ##\pm## to each component that describes the collision ...
Ssnow
I meant ##e_x## to be the coefficient of restitution. Sorry for not specifying. Anyways, I get it now. Thanks
 
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