Static engineering v -- stress/buckling

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oxon88
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Homework Statement



A column has the dimensions shown below...

untitled.GIF



Column material properties:

young's Modulus E = 200 GN m^-2

Yield stress = 140 MN m^-2




Homework Equations




a) what is the minimum length of the column at which buckling is likely to occur?



The Attempt at a Solution




i got an answer of: 2*((118.74 * Sqrt((2.33x10^3)/(2800x10^-3))) = 6850.56 M
 
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oxon88: Your current answer is wrong. Try again. First, list relevant equations. And then show how you computed each numerical value used in your final equation.

By the way, MN*m^-2 is called MPa. And GN*m^-2 is called GPa. Always use the correct, special name for a unit. E.g., 140 MPa, not 140 MN*m^-2.
 

Homework Statement



a) what is the minimum length of the column at which buckling is likely to occur?


The Attempt at a Solution




least second moment of area. I = (B^4 - b^4)/12 = (80^4 - 60^4)/12 = 2.33x10^6

area. A = B^2 - b^2 = 80^2 - 60^2 = 2800

σ = 140x10^6

E = 200x10^9

effective slenderness ratio. E.S.R = sqrt(pi^2.E/σ) = sqrt(pi^2.(200x10^9)/(140x10^6)) = 118.74

effective length. L = (E.S.R). Sqrt(I/A) = 118.74(sqrt(2.33x10^3)/(2800)) = 3427.7


effective length = 1/2 column length. = 3427 x 2 = 6854 mm


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I also tried another method and got the same answer...


Least value of radius of gyration. K = (1/2).sqrt((B^2+b^2)/3) = 1/2 sqrt((80^2+60^2)/3) = 28.868

effective length. L = (E.S.R x k) = 28.868 x 118.74 = 3427.73

effective length = 1/2 column length. = 3427 x 2 = 6854 mm
 
ok. So if the column was to be 5.94 m. What would be the mode of failure? and at what load would you expect the failure to occur?

I guess it would be buckling?
 
We are not allowed to answer your homework questions for you.
 
Hi all, I have the same question and was getting the same answers originally. I assume that your new answer is based on changing the formula to a hollow tube. I was wondering without being told in the question how we are supposed to determine what shape it is... Or am I being a bit thick...
 
Wrong formula

The least second moment of area I about the xx axis is not what you stated so your value is incorrect. I get L = 5.236389088 m
 
I am just wondering if this thread is still active as I am studying this question and facing similar problems to those on here
 
David J said:
I am just wondering if this thread is still active as I am studying this question and facing similar problems to those on here
The last post was two years ago, so, no, it's not still active. :frown:

However, you can and should create your own, fresh thread. It's not like you can create only so many threads at PF before you run out. :wink: