Column buckling in a pin jointed structure

Click For Summary
SUMMARY

In the discussion on column buckling in pin-jointed structures, it is established that bar BC is the first to buckle due to its combination of the highest compressive force and longer length. The critical buckling behavior is influenced by both the magnitude of the compressive force and the length of the bar. A shorter bar with a high compressive force may not necessarily be the critical buckling member, as the overall stability is determined by the interaction of these factors. It is essential to evaluate each member's compressive stress against the material's yield strength to prevent failure.

PREREQUISITES
  • Understanding of Euler's buckling theory
  • Knowledge of compressive forces in structural members
  • Familiarity with material yield strength concepts
  • Experience with pin-jointed structural analysis
NEXT STEPS
  • Study Euler's critical load formula for different column lengths
  • Explore the effects of slenderness ratio on buckling behavior
  • Learn about the design principles for compression members in structural engineering
  • Investigate the role of boundary conditions in buckling analysis
USEFUL FOR

Structural engineers, civil engineering students, and professionals involved in the design and analysis of compression members in pin-jointed frameworks.

xJJx
Messages
56
Reaction score
2
<< Mentor Note -- thread moved from the schoolwork forums to the ME forum because it's more of a general question >>

Hi, in these column bucking notes (photo attached below) it says that bar BC will buckle first out of all the other bars in compression, but it does not explain why. I know it has the highest compressive force in it and also the longer length, but what if the bar had the highest comrpessive force but the shortest length? Would it still be the critical bar?
 

Attachments

  • 13AE4AE4-5959-4C46-9F39-E19B215141DB.jpeg
    13AE4AE4-5959-4C46-9F39-E19B215141DB.jpeg
    16.2 KB · Views: 482
Last edited by a moderator:
Engineering news on Phys.org
It didn't explain why, but you did nicely. If there was a different problem where there were to be a larger force in a compression member with smaller length, you'd have to check that one also to see which controls for the compression case. Or you might have a smaller load and longer length that controls. While in any case not exceeding the yield or breaking or failure compressive stress of the material.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
6
Views
2K
Replies
3
Views
4K
Replies
5
Views
3K
Replies
13
Views
4K
Replies
9
Views
2K
Replies
2
Views
2K
  • · Replies 47 ·
2
Replies
47
Views
27K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K