Combination of Capacitors and Equivalent Capacitance

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SUMMARY

The discussion centers on calculating the charge on capacitor C1 in a network of capacitors with given capacitance values: C1 = 6.00 μF, C2 = 3.10 μF, C3 = 2.20 μF, C4 = 1.30 μF, C5 = 4.40 μF, and C6 = 6.50 μF, with an equivalent capacitance (Ceq) of 4.994 × 10-6 F and a supply voltage of 20V. The participants clarify that capacitors in series share the same charge, while those in parallel share the same voltage. The correct method to find the charge on C1 involves using the formula Q = CV, applying the total charge found from Ceq and distributing it according to the capacitance values of the capacitors in parallel.

PREREQUISITES
  • Understanding of capacitor configurations (series and parallel)
  • Familiarity with capacitance values in microfarads (μF)
  • Knowledge of the relationship between charge, capacitance, and voltage (Q = CV)
  • Basic principles of electrical circuits
NEXT STEPS
  • Study the principles of charge distribution in parallel and series capacitor networks
  • Learn how to calculate equivalent capacitance for complex capacitor arrangements
  • Explore practical applications of capacitors in electronic circuits
  • Review the effects of voltage on charge distribution across capacitors
USEFUL FOR

Students in electrical engineering, electronics enthusiasts, and anyone seeking to understand capacitor behavior in circuits will benefit from this discussion.

arl146
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Homework Statement


Calculate the charge on C1 in Coulombs.


Homework Equations


umm q=CV



The Attempt at a Solution



http://answers.yahoo.com/question/index?qid=20120424171750AA1WxRv

I have this same problem except my numbers are:
C1= 6.00 μF, C2=3.10 μF, C3= 2.20 μF, C4= 1.30 μF, C5=4.40 μF, C6=6.50 μF
and my Ceq = 4.994×10-6 F

I don't understand when the person says: "Then you have to split up the 2.6 MC
to assign parts of it to C1 and part of it to C6, proportionally."
how do i do that?
 
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I really don't understand how to get the charge across C1 ??
 
The given answer errs in that the charge on the capacitor network cannot possibly be in the MEGA coulomb range. MICRO coulombs would be indicated by the fact that the capacitances are on the order of microfarads and the supply is only 20V.

The statement about splitting the charge is correct; how does charge divide between parallel capacitors (they have the same potential difference)?
 
arl146 said:
I really don't understand how to get the charge across C1 ??

Voltages are ACROSS, currents are THROUGH, and charges are ON :wink:
 
well i was thinking something like i can find the total charge by Ceq(V) where V=20 and Ceq =4.994x10^(-6)

so i have a total charge now. looking at the whole thing, Ceq is for C16 in series with C2345 meaning that those two have the same charge but split voltage. so wouldn't the charges each just be (4.994x10^(-6))/2 and the voltage 10V for each?

and when i do that i look further into C16. since C16 are parallel, they have the same voltage across but different charges. Q1 = C1(V) where V is 10 and Q6 = C6(V)? but that's not right
 
arl146 said:
well i was thinking something like i can find the total charge by Ceq(V) where V=20 and Ceq =4.994x10^(-6)

so i have a total charge now. looking at the whole thing, Ceq is for C16 in series with C2345 meaning that those two have the same charge but split voltage. so wouldn't the charges each just be (4.994x10^(-6))/2 and the voltage 10V for each?
Nope. Capacitors in series have the same charge. This must be so since it's current that "delivers" the charge, and series components MUST have the same current. This also means that the voltages need not be the same, since the same charge on different capacitances will yield different voltages.
and when i do that i look further into C16. since C16 are parallel, they have the same voltage across but different charges. Q1 = C1(V) where V is 10 and Q6 = C6(V)? but that's not right
True; the voltage across them is not 20V/2. Use the charge that you found and apportion it according to the capacitance values.
 
i don't know how! I am so lost
 
i got it ;)
thanks for your help
 

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