- #1
mehrts
- 15
- 0
You're playing standard bridge with three other people. If you know that you and your partner have 10 hearts altogether, then what is the probability that the remaining 3 hearts are all in the same hand ?
Is it comb(3,3)*comb(23,10)/comb(26,13) ? Since there is only 1 way of selecting 3 hearts and com(23,10) ways of selecting the other 10 cards and comb(26,13) different combinations for the opponents cards ?
Is it comb(3,3)*comb(23,10)/comb(26,13) ? Since there is only 1 way of selecting 3 hearts and com(23,10) ways of selecting the other 10 cards and comb(26,13) different combinations for the opponents cards ?