Hello PF! 1. The problem statement, all variables and given/known data The graph of the function y = 2x2 + x +1 is stretched vertically about the x-axis by a factor of 2, stretched horizontally about the y-axis by a factor of 1/3 and translated 2 units right and 4 units down. Write the equation of the transformed function 2. Relevant equations y= af(1/b(x-h))+k 3. The attempt at a solution First I completed the square of y = 2x2 + x +1: 2x2 + x +1 = y 2(x2+1/2x+1/16-1/16)+1=y 2(x+1/4)2+14/16=y Then, using mapping notation I calculated what the new x and y coordinates would be on the transformed function: (x,y) → (1/3x+2,2y-4) Therefore, the point (-2,7) → (4/3,10) Using the aforementioned equation I transformed the function: a=2 b=1/3 h=2 k=-4 y=2(2(3(x-7/4)2)-25/8) However, when I input the new function into my calculator I received the values (-2,7) → (4/3,53/9) which is demonstrated to be incorrect. Is there a way to solve this problem without putting the function in the form y= af(1/b(x-h))+k? If possible, can anyone show me how to derive the correct equation for the transformed function after completing the square of the function? Thanks!