Combining Vectors: Calculate Resultant | Matthew vonFat

  • Thread starter Thread starter MattVonFat
  • Start date Start date
  • Tags Tags
    Vectors
AI Thread Summary
The discussion centers on calculating the resultant of two vectors, with the user arriving at a magnitude of 116.037N and a direction of 10.04° below the horizontal. However, the course material provides a different answer of 76.97N at 15.24° below the horizontal. The user meticulously details their calculations for the horizontal and vertical components of both vectors, leading to their resultant. Other participants confirm the user's calculations are correct and suggest the course material contains an error. The conversation highlights the importance of verifying answers against reliable sources, especially in educational contexts.
MattVonFat
Messages
8
Reaction score
0
It's not exactly homework as it's a progress check question in a home learning course but I think this is the best place for it.

Homework Statement



The question I have is:

Calculate the resultant of the two vectors shown:

[PLAIN]http://www.mattvonfat.com/question.png


The Attempt at a Solution



Here's my problem, I've come up with the magnitude of the resultant as 116.037N and the direction 10.04° below the horizontal. The course gives the answer as 76.97N at 15.24° below the horizontal.

I've gone over the material again however it seems that the answer the course book gives is still wrong. I also tried putting the vectors into the vector addition applets and calculators on web pages but they don't give the answer the course gives me either.

Here's how I worked it:

Code:
Horizontal Component of 60N vector = 60cos 35
                                   = 49.15N

Vertical Component of 60N Vector    = 60sin 35
                                    = 34.41N

Horizontal Component of 85N vector = 85cos 40
                                   = 65.11N

Vertical Component of 85N vector    = -85sin 40
                                    = -54.64N

Total Horizontal = 49.15 + 65.11 = 114.26N

Total Vertical = 34.41 - 54.64 = -20.23N

Then I use those values for the sides of a right angled triangle and the hypotenuse/magnitude of the vector is:

h² = 114.26² + -20.23²
h² = 13464.6
h = 116.037N

and the angle (a):

Tan a = -20.23 / 114.26
a = Tan[SUP]-1[/SUP] 0.177
a = -10.04°

Is there a problem with they way I have done it or is the course wrong?

Thanks for any help you can offer,
Matthew
 
Last edited by a moderator:
Physics news on Phys.org
Looks spot on to me.

The only place to make sure you keep an eye out is with significant figures. Depending on how closely someone wants to argue it, there are either 2 or 1 significant figure(s). But overall, very clearly and cleanly worked. :approve:
 
Your work is correct; the book has the wrong answer (I hate it when that happens)
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top