Comet Speed at 6x10^12 m from Sun

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A comet follows an elliptical orbit around the Sun, with its closest approach at 4.7x10^10 m and a speed of 9.6x10^4 m/s. To determine its speed at a distance of 6x10^12 m, conservation of energy principles can be applied, considering both potential and kinetic energy. The potential energy at the farthest distance can be calculated using the mass of the Sun, while the mass of the comet can be canceled out in the equations. The discussion emphasizes the need to understand energy conservation to solve for the comet's speed at this distance. This approach will yield the required speed at 6x10^12 m from the Sun.
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A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.7x10^10 m (inside the orbit of Mercury), at which point its speed is 9.6x10^4 m/s. Its farthest distance from the Sun is far beyond the orbit of Pluto. What is its speed when it is 6x10^12 m from the Sun? (This is the approximate distance of Pluto from the Sun.)



I have no idea how to do this can someone please help?
 
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conservation of energy. You know the potential energy and the kinetic energy at the closest point to the sun, and the potential energy at 6*10^12 m. All energies will contain the mass of the comet, but you can cancel that. You'll have to look up the mass of the sun.
 
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